The perimeter of a triangular field is 240 m
Webb- Cuemath. The perimeter of a triangular field is 420 m and its sides are in the ratio 6 : 7 : 8. Find the area of the triangular field - The perimeter of a triangular ... Problem Set 1 [d49g790vzon9]. 19. WEIGTHED MEASUREMENTS. Three sides of the triangle were measured with the following results: a=1431.20 m ± 0.02 m, b= 570.77 m ± 0.03 m ... Webband CD = 27 m in equation (1), we have. BD 2 = 48 x 27. ⇒ BD 2 = 1296. ⇒ BD = 36 m. The altitude of the triangle corresponding to its largest side is BD = 36 m (iii) The area of the triangular field from subpart (i) is 1350 m 2. The cost of levelling the field is Rs. 10 per square metre, Thus the total cost of levelling the field = 1350 x ...
The perimeter of a triangular field is 240 m
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WebbProblem (CE Board) A point O is inside an equilateral triangular lot ABC.Point O is 3 m from corner A, 4 m from corner B, and 5 m from corner C.Compute the area of the lot. A. 16.70 m² B. 17.95 m² C. 18.72 m² D. 19.85 m² Watch the solution (GERTC+) Problem. Find the length of the altitude of an isosceles triangle if its base is 8 units and the equal sides are … WebbThe perimeter of a triangular field is 240m, and its sides are in the ratio 25:17:12. Find the area of the field. Also find the cost askedJul 20, 2024in Perimeter and Area of Plane Figuresby Dheeya(31.0kpoints) perimeter and area class-10 0votes 1answer The perimeter of a triangular field is 540 m, and its sides are in the ratio 25:17:12.
Webb24 feb. 2024 · 6. Add up the lengths of the three side lengths to find the perimeter. Recall that the perimeter P = a + b + c. Now that you know the lengths of sides a, b and c, you simply need to add the lengths together to find the perimeter. In our first example, P = 3 + 4 + 5, or 12. In our second example, P = 6 + 8 + 10, or 24 . WebbEssentially, the factors of 24, and then figure out which of those satisfy the perimeter up here. Where if I take the width plus the width-- essentially 2 times the width plus 2 times the length-- I am going to get to 20. So let's figure that out. So let me make two columns here. So one column, I'm going to call it a width column.
Webb22 feb. 2024 · A = 1 2 × b × h. . Hence, to find the area of a tri-sided polygon, we have to know the base (b) and height (h) of it. Consider the given question: Given the perimeter … Webb29 mars 2024 · In another triangular field with sides 240 m, 320 m, 400 m adjacent to the previous field, she wanted to grow potatoes and onions. She divided the field in two parts by joining the mid-point of the longest side to the opposite vertex and grew potatoes in one part and onions in the other part.
WebbSolution for Three Perimeter and Area Math Questions How can I solve and answer these three math questions on Perimeter and Area ... The triangular deck is a right triangle, with legs of length 9 feet and 11 feet, and ... Find the exact area of the pool. arrow_forward. Width of a Lawn A factory is to be built on a lot measuring 180 ft by 240 ft.
WebbAns. Perimeter of the triangle = 540 cm. ⇒ Semi–perimeter of the triangle, ∴ The sides are in the ratio of 12 : 17 : 25. ∴ a ... If each side of the rhombus is 30: m and its longer diagonal is 48 m, how much area Of grass field will each cow be getting? Ans. Here, each side of the rhombus = 30 m. chrysalis spiritual meaningWebbSolution Perimeter of the field = 144 m Ratio in the sides = 3 : 4 : 5 Sum of ratios -3 + 4 + 5 = 12 ∴ First side = 14412×3=36m Second side = 14412×4=48m and third side = 14412×5=60m Now, s=P erimeter2=1442=72m ∴ Area = √s(s−a)(s−b)(s−c) = √72(72−36)(72−48)(72−60) = √72×36×24×12 = √12×2×3×12×3×12×2×12 = … derryberry heatingWebbThe perimeter of a triangular field is \( 240 \mathrm{dm} \). If two of its sides are \( 78 \mathrm{dm} \) and \( 50 \mathrm{dm} \), find the length of the p... chrysalis stamford field coatWebb18 mars 2024 · Now we will calculate the value of semi perimeter by dividing above result by 2. We get, Semi perimeter of triangular field = $\dfrac{{a + b + c}}{2}$ We get, = $\dfrac{{250}}{2}m$ Dividing 250 by 2 in above equation we get, Semi perimeter= $125m$ Now, putting the values of semi perimeter and sides of triangular field we get, derryborough.orgWebbThe perimeter of a triangular field is \( 240 \mathrm{dm} \). If two of its sides are \( 78 \mathrm{dm} \) and \( 50 \mathrm{dm} \), find the length of the p... derry beverage washingtonville pahttp://aven.amritalearning.com/index.php?sub=102&brch=305&sim=1596&cnt=3886 chrysalis steiner school — thoraWebbArea of triangle = ½ × base × height Substituting the values 336 = ½ × 20 × h By further calculation h = (336 × 2)/ 20 So we get h = 336/10 h = 33.6 cm Hence, the required altitude of the triangle is 33.6 cm. 4. The sides of a triangular field are 975 m, 1050 m and 1125 m. chrysalis stage merriweather